Integrand size = 27, antiderivative size = 140 \[ \int \frac {A+B \log \left (\frac {e (a+b x)}{c+d x}\right )}{f+g x} \, dx=-\frac {B \log \left (-\frac {g (a+b x)}{b f-a g}\right ) \log (f+g x)}{g}+\frac {\left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{g}+\frac {B \log \left (-\frac {g (c+d x)}{d f-c g}\right ) \log (f+g x)}{g}-\frac {B \operatorname {PolyLog}\left (2,\frac {b (f+g x)}{b f-a g}\right )}{g}+\frac {B \operatorname {PolyLog}\left (2,\frac {d (f+g x)}{d f-c g}\right )}{g} \]
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Time = 0.10 (sec) , antiderivative size = 140, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.148, Rules used = {2546, 2441, 2440, 2438} \[ \int \frac {A+B \log \left (\frac {e (a+b x)}{c+d x}\right )}{f+g x} \, dx=\frac {\log (f+g x) \left (B \log \left (\frac {e (a+b x)}{c+d x}\right )+A\right )}{g}-\frac {B \operatorname {PolyLog}\left (2,\frac {b (f+g x)}{b f-a g}\right )}{g}-\frac {B \log (f+g x) \log \left (-\frac {g (a+b x)}{b f-a g}\right )}{g}+\frac {B \operatorname {PolyLog}\left (2,\frac {d (f+g x)}{d f-c g}\right )}{g}+\frac {B \log (f+g x) \log \left (-\frac {g (c+d x)}{d f-c g}\right )}{g} \]
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Rule 2438
Rule 2440
Rule 2441
Rule 2546
Rubi steps \begin{align*} \text {integral}& = \frac {\left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{g}-\frac {(b B) \int \frac {\log (f+g x)}{a+b x} \, dx}{g}+\frac {(B d) \int \frac {\log (f+g x)}{c+d x} \, dx}{g} \\ & = -\frac {B \log \left (-\frac {g (a+b x)}{b f-a g}\right ) \log (f+g x)}{g}+\frac {\left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{g}+\frac {B \log \left (-\frac {g (c+d x)}{d f-c g}\right ) \log (f+g x)}{g}+B \int \frac {\log \left (\frac {g (a+b x)}{-b f+a g}\right )}{f+g x} \, dx-B \int \frac {\log \left (\frac {g (c+d x)}{-d f+c g}\right )}{f+g x} \, dx \\ & = -\frac {B \log \left (-\frac {g (a+b x)}{b f-a g}\right ) \log (f+g x)}{g}+\frac {\left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{g}+\frac {B \log \left (-\frac {g (c+d x)}{d f-c g}\right ) \log (f+g x)}{g}+\frac {B \text {Subst}\left (\int \frac {\log \left (1+\frac {b x}{-b f+a g}\right )}{x} \, dx,x,f+g x\right )}{g}-\frac {B \text {Subst}\left (\int \frac {\log \left (1+\frac {d x}{-d f+c g}\right )}{x} \, dx,x,f+g x\right )}{g} \\ & = -\frac {B \log \left (-\frac {g (a+b x)}{b f-a g}\right ) \log (f+g x)}{g}+\frac {\left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{g}+\frac {B \log \left (-\frac {g (c+d x)}{d f-c g}\right ) \log (f+g x)}{g}-\frac {B \text {Li}_2\left (\frac {b (f+g x)}{b f-a g}\right )}{g}+\frac {B \text {Li}_2\left (\frac {d (f+g x)}{d f-c g}\right )}{g} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 115, normalized size of antiderivative = 0.82 \[ \int \frac {A+B \log \left (\frac {e (a+b x)}{c+d x}\right )}{f+g x} \, dx=\frac {\left (A-B \log \left (\frac {g (a+b x)}{-b f+a g}\right )+B \log \left (\frac {e (a+b x)}{c+d x}\right )+B \log \left (\frac {g (c+d x)}{-d f+c g}\right )\right ) \log (f+g x)-B \operatorname {PolyLog}\left (2,\frac {b (f+g x)}{b f-a g}\right )+B \operatorname {PolyLog}\left (2,\frac {d (f+g x)}{d f-c g}\right )}{g} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(371\) vs. \(2(140)=280\).
Time = 3.98 (sec) , antiderivative size = 372, normalized size of antiderivative = 2.66
method | result | size |
parts | \(\frac {A \ln \left (g x +f \right )}{g}-\frac {B \left (a d -c b \right ) e \left (-\frac {d^{2} \left (c g -d f \right ) \left (\frac {\operatorname {dilog}\left (\frac {\left (c g -d f \right ) \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right )-a e g +b e f}{-a e g +b e f}\right )}{c g -d f}+\frac {\ln \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) \ln \left (\frac {\left (c g -d f \right ) \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right )-a e g +b e f}{-a e g +b e f}\right )}{c g -d f}\right )}{e g \left (a d -c b \right )}+\frac {d^{3} \left (\frac {\operatorname {dilog}\left (-\frac {\left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) d -b e}{b e}\right )}{d}+\frac {\ln \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) \ln \left (-\frac {\left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) d -b e}{b e}\right )}{d}\right )}{e g \left (a d -c b \right )}\right )}{d^{2}}\) | \(372\) |
derivativedivides | \(-\frac {e \left (a d -c b \right ) \left (-d^{2} A \left (-\frac {\left (c g -d f \right ) \ln \left (a e g -b e f -c g \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right )+d f \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right )\right )}{e g \left (a d -c b \right ) \left (-c g +d f \right )}-\frac {\ln \left (b e -\left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) d \right )}{e g \left (a d -c b \right )}\right )-d^{2} B \left (\frac {\left (c g -d f \right ) \left (\frac {\operatorname {dilog}\left (\frac {\left (c g -d f \right ) \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right )-a e g +b e f}{-a e g +b e f}\right )}{c g -d f}+\frac {\ln \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) \ln \left (\frac {\left (c g -d f \right ) \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right )-a e g +b e f}{-a e g +b e f}\right )}{c g -d f}\right )}{e g \left (a d -c b \right )}-\frac {d \left (\frac {\operatorname {dilog}\left (-\frac {\left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) d -b e}{b e}\right )}{d}+\frac {\ln \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) \ln \left (-\frac {\left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) d -b e}{b e}\right )}{d}\right )}{e g \left (a d -c b \right )}\right )\right )}{d^{2}}\) | \(529\) |
default | \(-\frac {e \left (a d -c b \right ) \left (-d^{2} A \left (-\frac {\left (c g -d f \right ) \ln \left (a e g -b e f -c g \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right )+d f \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right )\right )}{e g \left (a d -c b \right ) \left (-c g +d f \right )}-\frac {\ln \left (b e -\left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) d \right )}{e g \left (a d -c b \right )}\right )-d^{2} B \left (\frac {\left (c g -d f \right ) \left (\frac {\operatorname {dilog}\left (\frac {\left (c g -d f \right ) \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right )-a e g +b e f}{-a e g +b e f}\right )}{c g -d f}+\frac {\ln \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) \ln \left (\frac {\left (c g -d f \right ) \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right )-a e g +b e f}{-a e g +b e f}\right )}{c g -d f}\right )}{e g \left (a d -c b \right )}-\frac {d \left (\frac {\operatorname {dilog}\left (-\frac {\left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) d -b e}{b e}\right )}{d}+\frac {\ln \left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) \ln \left (-\frac {\left (\frac {b e}{d}+\frac {\left (a d -c b \right ) e}{d \left (d x +c \right )}\right ) d -b e}{b e}\right )}{d}\right )}{e g \left (a d -c b \right )}\right )\right )}{d^{2}}\) | \(529\) |
risch | \(\text {Expression too large to display}\) | \(1127\) |
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\[ \int \frac {A+B \log \left (\frac {e (a+b x)}{c+d x}\right )}{f+g x} \, dx=\int { \frac {B \log \left (\frac {{\left (b x + a\right )} e}{d x + c}\right ) + A}{g x + f} \,d x } \]
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Timed out. \[ \int \frac {A+B \log \left (\frac {e (a+b x)}{c+d x}\right )}{f+g x} \, dx=\text {Timed out} \]
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\[ \int \frac {A+B \log \left (\frac {e (a+b x)}{c+d x}\right )}{f+g x} \, dx=\int { \frac {B \log \left (\frac {{\left (b x + a\right )} e}{d x + c}\right ) + A}{g x + f} \,d x } \]
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\[ \int \frac {A+B \log \left (\frac {e (a+b x)}{c+d x}\right )}{f+g x} \, dx=\int { \frac {B \log \left (\frac {{\left (b x + a\right )} e}{d x + c}\right ) + A}{g x + f} \,d x } \]
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Timed out. \[ \int \frac {A+B \log \left (\frac {e (a+b x)}{c+d x}\right )}{f+g x} \, dx=\int \frac {A+B\,\ln \left (\frac {e\,\left (a+b\,x\right )}{c+d\,x}\right )}{f+g\,x} \,d x \]
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